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Fundamental to many of the constructions we want to consider
in the following sections is the chain rule:
Theorem 1.1 (Chain Rule.)
Let

be open ,

,

open and

with

.
Let

. Then:
The composition on the right hand
side is the composition of linear operators. In particular
if we expand both sides in terms of the standard basis
of
then we have
An important part of the chain rule is the fact that the
composition of smooth functions is also smooth. A partial
converse of this result will be important in the sequel.
Lemma 1.1
Let

be an open subset of

and

an
open subset of

. A function

is smooth if and only if for
every smooth function

the composite

is smooth.
Proof.
If

is smooth then the result follows via
the chain rule. If the result is true then take

to be
the restriction to

of each of the co-ordinate
functions

. Then

is smooth
so

is smooth.
Next: Diffeomorphisms and the inverse
Up: Co-ordinate independent calculus.
Previous: Derivatives as linear operators.
  Contents
Michael Murray
1998-09-16